RD SHARMA SOLUTIONS 3.1 INVERSE TRIGONOMETRIC FUNCTIONS /

 1. Find the principal values of each of the following:-


☝ value of -root3/2 is Sin (-pye/3) 

  Sin inverse x = 1/sinx

  answer:- -pye/3


2. Sin inverse (cos 2pye/3)


Cos (2pye/3) is not in range -90 to +90

  so value of cos 2pye/3 is Sin (-pye/6)

Answer.= -pye/6


3. Sin inverse (root 3-1/2root2)


4. Sin inverse ( root 3+1/2 root2)



5. Sin inverse (n Cos 3pye/2)m




Comments

  1. UnknownNovember 5, 2021 at 12:14 AM

    Good marling sir🔥🅱️😂🇵🇰😂🇵🇰⚠️🏅😂🚩😂

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