RD SHARMA SOLUTIONS 3.1 INVERSE TRIGONOMETRIC FUNCTIONS /

1. Find the principal values of each of the following:- ☝ value of -root3/2 is Sin (-pye/3) Sin inverse x = 1/sinx answer:- -pye/3 2. Sin inverse (cos 2pye/3) Cos (2pye/3) is not in range -90 to +90 so value of cos 2pye/3 is Sin (-pye/6) Answer.= -pye/6 3. Sin inverse (root 3-1/2root2) 4. Sin inverse ( root 3+1/2 root2) 5. Sin inverse (n Cos 3pye/2)m